For what positive value of x does the tangent line to the curve y=ln(1-x) intersect the y-axis at the point (0,2)

0 < x < 1

Step-by-step explanation:

the derivative of the curve allows one to compute the slope:

(1/1-x) is the value of the slope, which depends of the point x. By using the line equation we have:

where yl is the tangent line of the original curve y in the point x.

For the intersection point (0,2), with b=2, we obtain:

The denominator must be different of zero. And the original curve y(x) only can take values of x < 1. Hence the positive value of x for the tangent line will be:

0 < x < 1

hope this helps!!

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743