A segment XD is drawn in rectangle QUAD as shown

below.

What are the measures of ZXDQ and ZUXD ?

mZXD

m2 UXD =

∠XDQ : 41°

∠UXD: 139 °

Step-by-step explanation:

Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.

A segment XD is drawn in rectangle QUAD as shown  below.

What are the measures of ∠XDQ and ∠UXD ?

My

As we can see in the photo, ∠ADX = 49° and ∠ADU =90°

=>  ∠XDQ = ∠ADU - ∠ADX

= 90°  - 49°  = 41°

In the triangle ADX, we can find out the angle of ∠DXA

= 180° - ∠DAX - ∠ADX

= 180° - 90° - 49°

= 41°

=> ∠UXD = 180° - ∠DXA  (Because UA is a straight line)

=180° - 41°  

= 139 °  

3x + 4y -25 =0 represents the amount of change sianna should recieve

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9