In section 1.1.1.3 we obtained an equation (1.1.26) that described the dynamic behavior of the load shaft speed as a function of the motor input voltage. starting from this equation, find the transfer function ωl(s) . vm (s)

The required transfer function is ,

Step-by-step explanation:

Given:

Consider a DC motor

To Find :

Transfer function of load shaft and Input voltage.

Solution:

(Refer the attachment because this website dont allows the some words and so written on paper )

............Equation(1)

............................Equation(2)

i.e. Electrical -mechanical equations we get,

E=K*Wm(t)

T(t)=Kt*Ia(t)...................... [ t is used since function are in Time domain]

Taking Laplace transform equation (1) and (2) we get ,

For Electrical,

.......................(Frequency domain)

For mechanical ,

And we know that

And,

And also

By definition of transfer function:

T.F.=      G(s)/[(1+H(s)*G(s)]

Using G(s) value in transfer function we get as ,

Wm(s)/Ea(s)=[

This is required transfer function

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right