At a point 400 feet from the base of a building, the angle of elevation to the top of the building is 60◦. Find the height of the building (leave your answer in radical form)

The height of the building is 400√3

Step-by-step explanation:

Given:

Angle of elevation to the top of the building = 60°

Distance from the observer to the base of it = 400 ft

We have to find the height of the building.

Let the height of the building be "h" ft

Using trigonometric ratio:

⇒

So,

Considering adjacent side as 400 ft.

⇒

⇒

⇒

⇒                         ...tan(60) = √3

⇒ ft

The height of the building is 400 Sq-rt (3) ft in terms of radical form and in decimals it is 692.8 ft.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

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step-by-step explanation: