How to solve for x in x² + 4x + 4 = 8 Explanation will get brainliest. Thanks guys!

x=−2±2√2

x=−2±4√ 2

x=−4±2√ 2

x=−4±4√ 2

x = -2 ±2sqrt(2)

Step-by-step explanation:

x² + 4x + 4 = 8

Lets solve by completing the square

The left is set for completing the square since (4/2)^2 =4  so we rewrite this as (x+4/2)^2

(x+2) ^2 = 8

Take the square root of each side

sqrt((x+2) ^2 ) = ±sqrt(8)

x+2 =±sqrt(4*2)

x+2  =±sqrt(4)sqrt(2)

x+2 = ±2sqrt(2)

Subtract 2 from each side

x+2-2 = -2 ±2sqrt(2)

x = -2 ±2sqrt(2)

Steps to solve:

x² + 4x + 4 = 8

~Subtract 8 to both sides

x² + 4x + 4 - 8 = 8 - 8

~Simplify

x² + 4x - 4 = 0

This is in standard form [ ax² + bx + c ], so we can find the a, b,  and c values.

a = 1

b = 4

c = -4

Use the quadratic formula [ ] to solve.

Therefore, the correct answer is x = −2 ± 2√2 (Option A)

Best of Luck!

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

one set of data has more variation than the other. hope this !