Sam rolled a die 75 times. On 39 of those rolls, he had a 6. Which statement is TRUE when the probabilities are compared?

A) The theoretical probability is twice the experimental probability.

B) The experimental probability and the theoretical probability are equal.

C) The theoretical probability is greater than the experimental probability.

D) The experimental probability is greater than the theoretical probability.

D) The experimental probability is greater than the theoretical probability.

Step-by-step explanation:

the theoretical probability says that each option (1, 2, 3, 4, 5, 6) will be rolled an even amount of times. to work this out, divide the total number of rolls (75) by the total amount of possibilities (6)

75 ÷ 6 = 12.5

so, theoretical probability says that each number should be rolled 12.5 times. The question says that 6 was rolled 39 times.

Theoretical P(6) =

Experimental P(6) =

the experimental probability is greater than the theoretical probability

∴  the answer is D

I hope this was helpful :-)

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

answer: h

step-by-step explanation: