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Find the line of symmetry for the parabola whose equation is y = 2x 2 - 4x + 1.

x = -1
x = 1
x = 2

x=1

Explain:

y=2x^2−4x+1

dy/dx=4x-4

The line of symmetry will be where the curve turns (due to the nature of the

x^2 graph.

This is also when the gradient of the curve is 0.

Therefore, let

dy/dx=0

This forms an equation such that:

4x−4=0

solve for x,

x=1

and line of symmetry falls on the line

x=1

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