What is the surface area of this square pyramid?
A;3600 yd2

B:6300 yd2

C:2925 yd2

D:2700 yd2 Please Help! (100 Points!)

A;3600 yd2

Step-by-step explanation:

The surface area is found by adding the area of the sides

The area of the bottom is

A= s^2 where s is the side length since it is a square

A = s^2 = 30^2= 900

We can find the area of one of the sides and multiply by 4 since all the sides are the same

The sides are triangles so

A = 1/2 bh  where b is the base b=30 and h is the height = 45

A = 1/2 (30)* 45

A = 675

We have 4 of these triangles

4*675 =2700

Add the 4 triangles and the bottom

2700+900

3600

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15