In ΔTUV, the measure of ∠V=90°, the measure of ∠U=55°, and VT = 82 feet. Find the length of TU to the nearest tenth of a foot.

Given:

Given that TUV is a right triangle with measure of ∠V=90°

The measure of ∠U = 55°, and the length of VT is 82 feet.

We need to determine the length of TU.

Length of TU:

The length of TU can be determined using the trigonometric ratio.

Thus, we have;

where , opp = VT and hyp = TU

Thus, we have;

Substituting the values, we have;

Simplifying, we have;

Thus, the length of TU is 100.1 feet.

the barter

the answer is d

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