WILL GIVE BRAINLIEST TO WHO CORRECTLY ANSWERS WITH WORK SHOWN
1. (a) Given the following equation, use synthetic division to test the following 3 pts and show which one is a root. Must show synthetic division for all 3 of the following test pts. Test these 3 possible root pts also called possible zeros
using synthetic division. (x, y) = (-1, 0) ; ( 1, 0) ; (2, 0).

Step-by-step explanation:

1. No function shown

2.  3x^2 - 7   =  0

Factors of p  = ±1, ±7

Factors of q =  ±1, ±3

Possible zeroes  =   ±1/3 , ±1, ±7/3, ±7

3.  No expression shown

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

step-by-step explanation:

a and d