A gardener wants to run a border around the outside of her garden. She plots it on a grid to plan how much she will
need. The garden is in the shape of a rectangle with vertices at (3.9) (5.9) (3, 3) (5, 3). Find the total length of border
needed.

Please help.

16 units.

Step-by-step explanation:

Just to make things easy, let's name the points A(3,9) B(5,9) C(3, 3) and D(5, 3).

Because this question wants perimeter, we'll just use the distance formula twice, then l*2 + w*2 = p.

Distance formula is sqrt((x1 - x2)^2 + (y1 - y2)^2) = d.

sqrt((5 - 3)^2 + (9 - 9)^2) = 2

sqrt((5 - 5)^2 + (9 - 3)^2) = 6.

The distance of points A and B is 2 units, and B to D is 6 units, multiply both by 2, (2*2=4, 6*2=12) and add the values to find 16 units.

Hope this helps, and if this is for OW, I feel your pain.

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐