Houseflies have pretty short lifespans. Males of a certain species have lifespans that are strongly skewed to the

right with a mean of 26 days and a standard deviation of 12 days. A biologist collects a random sample of 9 of

these male houseflies and observes them to calculate the sample mean lifespan.

What is the probability that the mean lifespan from the sample of 9 houseflies 2 is less than 24 days?

The probability that the mean lifespan from the sample of 9 houseflies is less than 24 days is 30.85%

Step-by-step explanation:

Given that:

number of samples (n) = 9 houseflies,

Mean (μ) = 26 days,

Standard deviation (σ) = 12 days.

The Z score is used in statistics to know by how much a value is above or below the mean. The Z score (z) is given by the equation:

To get the probability that the mean lifespan from the sample of 9 houseflies is less than 24 days (i.e x = 24)

From the z table:

P(x < 24) = P(z < -0.5) = 0.3085 = 30.85%

Therefore, the probability that the mean lifespan from the sample of 9 houseflies is less than 24 days is 30.85%

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2

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