A genetic experiment with peas resulted in one sample of offspring that consisted of 429 green peas and 163 yellow peas.

A) construct a 95% confidence interval to estimate of the percentage of yellow peas.

B)it was expected that 25% of the offspring peas would be yellow. given the percentage ofoffspring yellow peas is not 25% do the results contradict expectation?

A)__< p <__ (round the three decimal places as needed.)

B) given that the percentage of offspring yellow peas is not 25% do the results contradict expectation?

__ yes, the confidence interval does not include 0.25, so the true percentage could not equal 25%
__ no, the confidence interval include 0.25, so the true percentage could easly equal 25%

a) 0.239 < p < 0.311.

b) no, the confidence interval include 0.25, so the true percentage could easly equal 25%

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

163 yellow peas out of 163 + 429 = 592 total peas

So

95% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

So

A) 0.239 < p < 0.311.

B)

25% is part of the confidence interval.

So the answer is:

no, the confidence interval include 0.25, so the true percentage could easly equal 25%

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: