In a class of 30 students, 18 are men, 6 are earning a B, and no men are earning a B. If a student is randomly selected from the class, find the probability that the student is a man or earning a B. A) .8 B) .24 C) .54 D) .4

0.8

Step-by-step explanation:

The question here says that In a class of 30 students, 18 are men, 6 are earning a B, and no men are earning a B. If a student is randomly selected from the class, find the probability that the student is a man or earning a B.

Since the question says that 18 out of 30 students are men,6 out of the remaining people earn a "B" and non of the 18 men earn a "B".

The probability of picking a man or a person that earns a "B" is

18/30 (since there are 18 men out of the 30 students)

And 6/30(since there are 6 people that earn a "b")

The probability of picking a man or a "b" earner is

18/30 + 6/30

= 24/30 or 0.8

darn right!

step-by-step explanation:

steve kerr's sons name is let that skin in.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)