A white card has an 8 on one side and an unknown number on the other side. A red card has a 4 on one side with a different unknown number on the other side. Of the two cards are flipped, the four possible total scores are 12, 13, 14,15.Find two possible pairs of values, (W1, R1); (W2, R2), for the unknown numbers.

(10,5) and (9,6)

Step-by-step explanation:

•White card has 8 on one side and an unknown value on the other side. Let's take unknown value as p, i.e

Outcome of white card = (8, p)

•Red card has 4 on one side and unknown an the other side. Let's take q as the unknown figure on red card. I.e

Outcome of red card (4, q)

When the two cards are flipped the possible sum of their values will be:

•12 (8+4);

•8+q;

•4+p; and

•p+q

We are given that their sum values are 12, 13, 14 and 15

Therefore, let's now assume the following:

• 8+q = 13, or 8+q=14,

•4+p = 14, or 4+p = 13

Solving, we now have:

R1) 8+q = 13 => q= 13-8 = 5

or

R2) 8+q = 14=> q=14-8 = 6

W1) 4+p = 14 => p=14-4 = 10

or

W2) 4+p =13 => p=13-4 = 9

From the calculations, we can deduce that the two possible pair of values for the unknown nubers are:

(10,5) and (9,6)

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

let's fu(!

step-by-step explanation: