Which ordered pair makes both inequalities true?

y > –2x + 3

y < x – 2

On a coordinate plane, 2 straight lines are shown. The first solid line has a positive I I NEED HELP ASAP, QUICK slope and goes through (0, negative 2) and (2, 0). Everything to the right of the line is shaded. The second dashed line has a negative slope and goes through (0, 3) and (1, 1). Everything to the right of the line is shaded.
(0,0)
(0,–1)
(1,1)
(3,0)

(3,0)

Step-by-step explanation:

y > –2x + 3

y < x – 2

Graph the inequalities

We graph above the dotted line for y > –2x + 3   and below the dotted line for  y < x – 2

The solution is where the shaded areas overlap.

(3,0) is a solution

(3,0)

Step-by-step explanation:

y > –2x + 3

y < x – 2

(0,0)

0 > -2(0) + 3

0 > 3 --> true

0 < 0 - 2

0 < -2 --> false

(0,–1)

-1 > -2(0) + 3

-1 > 3 --> false

(1,1)

1 > -2(1) + 3

1 > 1 --> false

(3,0)

0 > -2(3) + 3

0 > -6 + 3

0 > -3 --> true

0 < 3 - 2

0 < 1 --> true

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.