What is the only solution of 2x2 + 8x = x2 - 16?

Assuming the equation is 2x^2+8=x^2-16
X= -4

Explanation:
(2x^2+8x)-(x^2-16)=0
You factor by splitting the middle term which gives you (x+4)^2=0
You then want to solve the single variable
(x+4)^2 represents a product of 2 terms which is equal to zero and since all these terms are equal to each other the equation should be x+4=0
Subtract 4 from both sides, you get x = -4

Idon’t exactly understand but i think dbc=rst