How do you model -9-(-4) with interger chips

Explanation:

Start with 9 negative chips, for a value of -9.

Take away (subtract) 4 of the negative chips. This is modeling - (-4).

You will be left with 5 negative chips.

  -9 - (-4) = -5

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Each negative chip in this scenario models -1. The actions you're doing with the chips are full equivalent to the actions you would do for the subtraction problem 9 - 4 = 5, except that the numbers (chips) are negative, not positive.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

sorry man i accidentally pressed yes my bad

step-by-step explanation: