How could you use coordinate geometry to prove that segment BC is congruent to segment AD?

Figure ABCD is shown. A is at negative 3, 2. B is at 0, 6. C is at 6, 6. D is at 3, 2.

A. Prove the slopes are the same.
B. Prove the slopes are opposite reciprocals.
C. Prove the lengths are the same.
D. Prove the midpoints are the same.

true

step-by-step explanation:

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .