Suppose that 43% of all adults in a certain community are obese and that 36% suffer from diabetes. If 20% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)? Write your answer as a decimal (not as a percentage)

0.59

Step-by-step explanation:

Since the probability of adults in this community that are both obese and suffering from diabetes overlap, when you add 43% and 36%, you count the percentage that overlap twice (Once the obese adults and once for the diabetic adults). Therefore, you have to subtract 20% from 43% + 36% so you only count the overlap once. Solving, 43% + 36% - 20% = 59%, or 0.59.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

hope to and hope that my answer is brainliest.(follow me )