What is true about the volume and surface area of a cube whose side length is 10 meters?

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

the graph line crosses the x axis at both -6 and -2, so the answer would be the second one.

to prove δxyz ≅ δmno using sss, you need to show the following:

  side 1             side 2               side 3

xy ≅ mn         yz ≅ no           xz ≅ mo

to prove δxyz ≅ δmno using sas knowing side xz and angle o, you need to show the following:

side 1             connecting angle           side 2

xz ≅ mo             ∠z ≅ ∠o                   yz ≅ no