What is the distance between the points (2 and one-half, negative 8) and (2 and one-half, 3) Sukant’s work is shown below?

StartAbsoluteValue 2 and one-half EndAbsoluteValue + StartAbsoluteValue 2 and one-half EndAbsoluteValue = 2 and one-half + 2 and one-half = 5. The distance is 5 units.

What error did Sukant make?

Given Information:

Point 1 = ( 2½, -8)

Point 2 = ( 2½, 3)

Required Information:

Distance between two points = d = ?

Distance between two points =

Step-by-step explanation:

The distance between two points is calculated using

  eq. 1

We have (x₁, y₁) = (2½, -8) and (x₂, y₂) = (2½, 3)

Substitute the above points into the eq. 1

it is very unclear as what error did Sukant make due to unclear typing!

But I guess, Sukant simply added the x-coordinates together that is

d = 2½ + 2½ = 5 units

Note: 2½ = 5/2 = 2.5

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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