What is the first step when rewriting y = 6x2 + 18x + 14 in the form y = a(x – h)2 + k?

y = 6(x -(-3/2))^2 - 13/12

Step-by-step explanation:

Given:

We have to write in vertex form y = a(x -h)^2 + k

Step 1: In the given function y = 6x^2 + 18x + 14, the coefficient of x^2 is 6, we need to make it 1, so we take out 6 and factor it.

y = 6(x^2 + 3x + 7/6)

x^2 + 3x + 7/6, the value of b = 3, now divided 3 by 2, then square it.

(3/2)^2 = 9/4

Now add and subtract 9/4

y = 6(x^2 + 3x +9/4 -9/4 + 7/6)

y = 6(x +3/2)^2 -9/4+ 7/6

y = 6(x -(-3/2))^2 +

Here we simplified -9/4 + 7/6 taking the LCD as 12

.

This can be written as

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

not me

step-by-step explanation:

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