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suppose x>-1. Simplify lx + 2l + lx + 5l

Please note that lxl the l part is absolute value
Please solve for the inequality of x

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2x + 7

Step-by-step explanation:

For x > -1,

x + 2 is positive

So, |x + 2| = x + 2

For x > -1,

x + 5 is positive

So, |x + 5| = x + 5

lx + 2l + lx + 5l = x + 2 + x + 5

= 2x + 7

Additional (in case range is also required)

lx + 2l

x > -1

lx + 2l > 1

lx + 5l

x > -1

lx + 5l > 4

lx + 2l + lx + 5l > 1 + 4

lx + 2l + lx + 5l > 5

2x+7  when x>-1

Step-by-step explanation:

lx + 2l + lx + 5l

We know that x > -1

Let x be -1  the minimum value

lx + 2l = l-1 + 2l = l1l  so it will always be greater than 0

We can remove the absolute value signs

Let x be -1  the minimum value

lx + 5l = l-1 + 5l = l4l  so it will always be greater than 0

We can remove the absolute value signs

x + 2+ x + 5  when x>-1

2x+7

step-by-step explanation:

no of data

divide by no of mode

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

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