Mathematics, 12.04.2020 06:25 AleOfficial101

Order the steps to solve the equation
log(x2 - 15) = log(2x) form 1 to 5.
-x² - 2x - 15=0

- Potential solutions are -3 and 5
-x² - 15= 2x

-X-5 = 0 orx+ 3 = 0

-(x - 5)(x + 3) = 0

Order the steps to solve the equation log(x2 - 15) = log(2x) form 1 to 5. -x² - 2x - 15=0 - Potentia

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Order the steps to solve the equation
log(x2 - 15) = log(2x) form 1 to 5.
-x² - 2x - 15=...

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Order the steps to solve the equation log(x2 - 15) = log(2x) form 1 to 5. -x² - 2x - 15=0 - Potential solutions are -3 and 5 -x² - 15= 2x -X-5 = 0 orx+ 3 = 0 -(x - 5)(x + 3) = 0

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Order the steps to solve the equation
log(x2 - 15) = log(2x) form 1 to 5.
-x² - 2x - 15=0

- Potential solutions are -3 and 5
-x² - 15= 2x

-X-5 = 0 orx+ 3 = 0

-(x - 5)(x + 3) = 0