Which of the following is the graph of f(x) = x2 − 6x + 5?

a
graph of a quadratic function with a minimum at 2, negative 9 and x intercepts at negative 1 and 5

b
graph of a quadratic function with a minimum at 3, negative 4 and x intercepts at 1 and 5

c
graph of a quadratic function with a minimum at 2.5, negative 2.4 and x intercepts at 1 and 4

d
graph of a quadratic function with a minimum at negative 1.5, negative 6.2 and x intercepts at 1 and negative 4

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof