If a rectangle has a width of
(4x+3) and a length of (x + 1)
what is the area of the
rectangle?

The rectangle doesn't exists

Step-by-step explanation:

(4x+3).(x+1)= ?

4x² + 4x + 3x + 3 = ?

4x² + 7x + 3 = ?

4 = a

7 = b

3 = c

delta = b² - 4.a.c

delta = 7² - 4.4.3

delta = 49 - 4.4.3

delta = 49 - 48

delta = 1

x1 = -b + (square root)delta / 2.a

x1 = -7 + 1/2.4

x1 = -6 / 8

x2 = -7 - 1/2.4

x2 = -8/8

x2 = -1

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

explanation:

step-by-step explanation: