Which statement is true concerning the vertex and axis of symmetry of h(x)=−2x2+8x?

the vertex is at (2, 8) and the axis of symmetry is x = 2

Step-by-step explanation:

In h(x)=−2x2+8x please use the symbol " ^ " to indicate exponentiation:

h(x)=−2x^2+8x      

This is a quadratic equation with coefficients a = -2, b = 8 and c = 0.

The axis of symmetry equation is x = -b/ (2a).

                                                                                                -8

Here, with a = -2 and b = 8, the axis of symmetry is   x = = 2

                                                                                               2(-2)

To find the y-coordinate of the vertex, substitute 2 for x in h(x)=−2x^2+8x, obtaining

h(2) = -2(2)^2 + 8(2) = -2(4) + 16 = 8

In summary, the vertex is at (2, 8) and the axis of symmetry is x = 2.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic