What is the sum of a 56-term arithmetic sequence where the first term is 6 and the last term is 391?

10,719
11,116
11,513
11,910

The sum of 56 term is 11,116

B is correct.

Step-by-step explanation:

Given:

First term , a=6

Last term l=391

n=56

Formula: Sum of nth term of Arithmetic series.

Substitute the value of a, l and n into formula.

Sum=11,116

Hence, The sum of 56 term is 11,116

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

answer is x<