Mathematics, 10.04.2020 22:16 cookiee835

Four congruent square pieces with lengths of sides of 6 cm were cut out of corners of a square piece of cardboard. Then this piece of cardboard was folded into an open-top box. Find the original dimensions of the piece of cardboard if the volume of the resulting box is 486 cm^3.

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The original dimensions of the cardboard is 21 cm × 21 cm, if a square pieces with lengths of sides of 6 cm were cut out of corners of a square piece of cardboard and the volume of the resulting box is 486 cubic centimeters.

Step-by-step explanation:

The given is,

Square pieces with lengths of sides of 6 cm were cut out of corners of a square piece of cardboard.

The volume of the resulting box is 486 cubic centimeters.

Step:1

The volume, is the given piece of cardboard was folded into an open box, we calculate side value of cardboard after cut into a square piece,

Formula for volume of cardboard is,

Volume, V = whl ......................(1)

Where, w - width

h - Height

l - length

From given, V= 486 cubic centimeters

h = 6 cm ( Ref attachment)

w = l

Equation (1) becomes,

$486=6(l^{2} )$

$l^{2} = 81$

Take root on both sides

l = 9 centimeters

Step:2

Ref the attachment,

Side value of piece of cardboard

= 6 + 9 + 6

= 21

Side value of piece of cardboard = 21 centimeters

original sides of cardboard is 21 cm × 21 cm

Result:

Four congruent square pieces with lengths of sides of 6 cm were cut out of corners of a square piece

Answer from: Quest

There is not enough information on this sorry can you take a picture of it and put it on here

Answer from: Quest

step-by-step explanation:

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Four congruent square pieces with lengths of sides of 6 cm were cut out of corners of a square piece...