Rewrite without absolute value for the given conditions:
y=|x−3|+|x+2|−|x−5|, if x>5

Step-by-step explanation:

hello :

y=|x−3|+|x+2|−|x−5|, if x>5

if x>5 :

|x−3| = x-3 because x-3>0

|x+2| = x+2 because x+2>0

|x−5| = x-5 because x-5>0

so : y = x-3+x+2-(x-5 )

y = 2x+4

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.