A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4 represents the height h (in feet) of the ball after t seconds. Using a graph, after how many seconds is the ball 30 feet above the ground? Round your answers to the nearest tenth.

I would like to know both the answer and the steps to get there please. Thank you!

Given:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

Time:

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

Adding both sides of the equation by 16t², we get;

Subtracting both sides of the equation by 55t, we have;

Let us solve the quadratic equation using the quadratic formula, we get;

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,