What is the process to both of these probabilities?

1) 25%

2) 27.2727272727%

Step-by-step explanation:

1) A Six-Sided dice only has six numbers, 1 through 6. This means that there is a 25% chance that the number rolled is going to be lower than 6. There is a 50% percent chance that one will roll a 3 or below. Think of it this way:

1  2  3          4  5  6

There are two lists above. Now if I pick a list, you will have a 50% chance of picking the one I picked. Now lets add another list.

1  2  3          4  5  6

7  8  9         10  11  12

Now you have a 25% chance of picking the same one as me. There are four options, and you have to pick the same on I did. You have a 1 in 4 chance.

2) If the numbers sum is at least 10, that leaves a possible 3 numbers. 10, 11, and 12. To get those numbers, both dice must be above three. If we take all of the possible sums, we get 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12. There are 11 numbers on that list. We have 3 out of the 11 possible sums. So lets put this in a fraction:

When we divide that, we get that we have a 27.272727% chance that the sums will be at least 10.

what are ur choices?