10 marbles. 4 are green, 2 are red, and 4 are blue. choosing a marble at random, and without putting it back, chooses another one at random. what is the probability that both marbles he chooses are blue.

12/90 = 6/45

Step-by-step explanation:

In the first draw the probability will be 4/10 because there are 4 blue marbles and 10 total marbles. In the second draw, since they did not put the marble back, the probability will be out of 9 marbles. There is also only 3 marbles, so the probability will be 3/9. Since you are calculating the probability of both combined, the answer will be 4/10 * 3/9 = 12/90 which simplifies to 6/45

the correct answer is 5

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b