One barge from Inland Waterways, Inc. can carry a load of 2555 lb. Records of past trips show that

the weights of the cans that it carries have a mean of 98 lb and a standard deviation of 10 lb. For

samples of size 25, find the mean and standard deviation of x.

A) x = 98; x = 2

B) x = 98; x = 10

C) x = 2; x = 98

D) x = 10; x = 98

Given values:

Sample mean,

Sample of size,

and,

Now,

The sample standard deviation will be:

=

By putting the values, we get

=

=

=

Thus the above choice i.e., "option A" is appropriate.

Learn more about mean here:

link

A) x = 98; x = 2

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

Samples of size 25

Mean 98

Standard deviation

So the correct answer is:

A) x = 98; x = 2

y=mx+b

step-by-step explanation:

m slope, b y-intercept

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5