5 barrels catch rainwater in the schoolyard. Four barrels are the same size, and the fifth barrel holds 10 liters of water. Combined, the 5 barrels can hold at least 200 liters of water. Write an inequality whose solution is the possible size of each of the 4 barrels.

How are these two problems similar? How are they different?

The volume each of the four barrels of the same size will be at least 47.5 liters.

Step-by-step explanation:

Let the volume of each of the four barrels is v liters.

Now, the amount of water that can be held in the fifth barrel is 10 liters. The total capacity of holding water for the 5 barrels combines is at least 200 liters.

So, from the above-given information, we can write the inequality to determine the volume of each of the four barrels will be  

10 + 4v ≥ 200

Solving this we get,

4v ≥ 190

⇒ v ≥ 47.5

Therefore, the volume each of the four barrels of the same size will be at least 47.5 liters. (Answer)

answer are

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it