What is the slope of the graph below?

O 1/5
O 1/3
O 3
O 5

Please answer

1/3

Step-by-step explanation:

We can use two points to find the slope

(0,-5) and (3,-4)

m = (y2-y1)/ (x2-x1)

   = (-4 - -5)/(3-0)

   = (-4+5)/(3-0)

   = 1/3

We can use the points (0,-5) and (3,-4) to solve.

Slope formula: y2-y1/x2-x1

= -4-(-5)/3-0

= 1/3

Therefore, the answer is the second option (1/3).

Best of Luck!

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐