A car is moving with an initial velocity of 10 mph accelerates at the rate of a(t)=2.5t mph per second for 5 seconds. How fast is the car going when the 5 seconds are up?

The car is going up at a speed of 22.5 mph

Step-by-step explanation:

In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.

To calculate this, we use one of the basic equations of motion;

v = u + at

Where v is the final velocity, u is the initial velocity and t is the time

From the question, we can identify the parameters as follows;

v = ?

u = 10mph

a = 2.5t mph per second for 5 seconds.

Hence a here would be 2.5 * 5 = 12.5

Now, let’s put these values in the equation

v = 10 + 12.5

v = 22.5 mph

4 + 5 7/9= 9 7/9

step-by-step explanation:

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.