A rectangular garden of area 480 square feet is to be surrounded on three sides by a brick wall costing $ 12 per foot and on one side by a fence costing $ 8 per foot. Find the dimensions of the garden such that the cost of the materials is minimized

Therefore the dimensions of the rectangular garden are 23.42 ft by 20.5 ft.

Step-by-step explanation:

Given that,

A rectangular garden of area 480 square feet.

Let length of the rectangular garden be x which is surrounded by fence and width of the rectangular garden be y.

Then xy is the area of the given rectangular garden .

Then,

xy= 480

The length of the tree sides which are surrounded by brick wall is = 2y+x.

The cost for the brick wall is =Length×cost per feet= $12(2y+x)

The cost for the fencing is =Length×cost per feet= $ 9x

Now putting

Differentiating with respect to x

Again differentiating with respect to x

Now we set C'=0

.

Since at x=23.42,C''>0. So at x=23.42, the total cost will be minimum.

The width of the rectangular garden is

Therefore the dimensions of the rectangular garden are 23.42 ft by 20.5 ft.

The cost of the material is

                                                 =$983.70

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

idk

step-by-step explanation: