The Palace of Peace and Accord in Astana, Kazakhstan, was built in 200620062006. The building has a square right pyramid structure. The length of a side of the square base is 62\,\text{m}62m62, start text, m, end text, and the vertical height of the pyramid is also 62\,\text{m}62m62, start text, m, end text.

What is the height, hhh, of one of the triangular faces?

Round your answer to the nearest tenth.

h= 69.3m

Step-by-step explanation:

The correct values in the question are:

year : 2006, length 62, vertical height 62.

So, the measure asked is called slant height . we have to apply the formula:

sh = √(vh^2 + [L/2]^2)

Where:  

vh= vertical height

L= length of a side of the square base

Replacing with the values given:

sh= √(62^2 + [62/2]^2)

sh = √(3,844 + 31^2)

sh= √(3,844 + 961)

sh = √4,805

hs= 69.31 =69.3 m (nearest tenth)

Since in the question that height is called h, h= 69.3

there still no table

192/15 = 12.8.

12.8

step-by-step explanation:

192/15 is 12.8.

however, it says to round to the nearest foot, which would equal 13.