Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?
f(x) = –x2 – 8x – 16
f(x) = –x2 + 8x – 16
f(x) = –x2 – 8x + 16
f(x) = –x2 + 8x + 16

Step-by-step explanation:

We are given that

Leading coefficient of second degree polynomial=-1

Roots of second degree polynomial=4,4 because multiplicity 2 means roots are repeated two times

We have to find the second degree polynomial function with leading coefficient -1 and root 4 with multiplicity 2.

General equation of second degree polynomial is given by

Substitute the values then we  get

  Using identity;()

Hence, the second degree polynomial function is given by

16

step-by-step explanation:

2 x 40 = 80

80/5

= 16