Two quadratic functions are shown. function 1: f(x) = 2x^2 − 8x 1 function 2: x g(x) −2 2 −1 −3 0 2 1 17 which function has the least minimum value and what are its coordinates? a. function 1 has the least minimum value and its coordinates are (0, 1). b. function 1 has the least minimum value and its coordinates are (2, −7). c. function 2 has the least minimum value and its coordinates are (0, 2). d. function 2 has the least minimum value and its coordinates are (−1, −3).

step-by-step explanation:

two quadratic functions are given.

hence vertex is at (2,-7)

the parabola is open up and hence minimum is (2,-7)

g(x) is given in tabular form as follows

x     -2     -1     0     1

g(x)   2   -3     2     17

we find from the table that minimum is at (-1,-3)

-7 < -3 hence

b)   function 1 has the least   minimum and its coordinates are (2,-7)

d) function 2 has the least minimum value and its coordinates are (−1, −3).

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.