Please Help!
The area of a rectangle is x^2 + 7x + 6. What is the perimeter of this rectangle?

 The perimeter would be  2(x+1) + 2(x+6) or  4x + 14

Such a rectangle does not really exist!

If you factor and solve for x, you get {-1,-6} Real Rectangles cannot have negative dimensions.

Step-by-step explanation: Factoring to find out which theoretical dimensions were multiplied to get the imaginary area you get (x + 1) and (x + 6).

Perimeter is  Twice the length plus Twice the width. So substitute the "dimensions" into the formula to get 2(x+1) + 2(x+6)  distribute and simplify

2x + 2 + 2x + 12 = 4x + 14

step-by-step explanation:

where is the questions

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer