Mathematics, 12.11.2019 05:31 emmaty7845
Arectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. find the area of the rectangle. a. 2 to the 3 over 5 power inches squared b. 2 to the 4 over 5 power inches squared c. 2 inches squared d. 2 to the 2 over 5 power inches squared
Answers: 2
![\sqrt[5]{16}](/tpl/images/0370/2734/fc4b9.png)
inches and width is 
inches. We are asked to find the area of the given rectangle.
![\text{Area of rectangle}=\sqrt[5]{16}\text{ Inches}\times 2^{\frac{1}{5}}\text{ Inches}](/tpl/images/0370/2734/fb268.png)
.![\text{Area of rectangle}=\sqrt[5]{2^4}\text{ Inches}\times 2^{\frac{1}{5}}\text{ Inches}](/tpl/images/0370/2734/6c045.png)
![\sqrt[n]{a^m}=a^\frac{m}{n}}](/tpl/images/0370/2734/4affe.png)
, we will get:
, we will get:
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Arectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches...
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