Acircular picture is 8 inches in diameter. part a. what is the area of the picture in square inches? a. 4π square inches b. 8π square inches c. 16π square inches d. 32π square inches part b. a frame that is 2 inches wide surrounds the picture. what is the total area of the picture and the frame in square inches? a. 4π square inches b. 12π square inches c. 36π square inches d. 40π square inches

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: