Assume the given distributions are normal. Cucumbers grown on a certain farm have weights with a standard deviation of 2 ounces. What is the mean weight if 85% of the cucumbers weigh less than 16 ounces?Assume the given distributions are normal. Group of answer choices14.4014.3014.8813.92

13.92

Step-by-step explanation:

We have that the critical z-score associated with 85% to the left is 1.04, we know that by table.

So we have to:

m + z * (sd) = 16

where m is the mean, z is the critical z-scor and sd is the standard deviation, if we replace we are left with:

m + 1.04 * (2) = 16

m = 16 - 1.04 * (2)

m = 13.92

Therefore, the average weight if 85% of cucumbers weigh less than 16 ounces is 13.92

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

5.25 ounces

step-by-step explanation:

divided 3/4 and 6