7. The length of time (in months after maintenance) until failure of a bank’s surveillance television equipment follows a Weibull distribution with α=2 and β=60. If the bank wants the probability of a breakdown before the next scheduled maintenance to be .05, how frequently should the equipment receive periodic maintenance?

The frequency by which the equipment should receive periodic maintenance is  

Step-by-step explanation:

A Wellbull distribution is mathematically represented as

Where x is the frequency that the equipment should receive periodic maintenance  

probability of a breakdown before the next scheduled maintenance is mathematically represented as

Substituting 2 for and 60 for 0.05 for P(x)

Let

=>  

=>  

Multiply both sides by minus

=>

Substituting this into the equation

Integrating and substituting back for x

    substituting for  the range of x and 0

Taking ln of both sides

     making x the  subject of the formula

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer is  

d.

a circle

i got it down for you chief.