The average starting salary for this year's graduates at a large university (LU) is $30,000 with a standard deviation of $6,000. Furthermore, it is known that the starting salaries are normally distributed. Answer the following question - Individuals with starting salaries of less than $15,600 receive a low income tax break. What percentage of the graduates will receive the tax break

0.82% of the graduates will receive the tax break

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

What percentage of the graduates will receive the tax break

This is the pvalue of Z when X = 15600. So

has a pvalue of 0.0082

0.82% of the graduates will receive the tax break

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.