G Let Z be the set of all nonzero integers. (a) Use a counterexample to explain why the following statement is false: For each x 2 Z , there exists a y 2 Z such that xy D 1. (b) Write the statement in part (a) in symbolic form using appropriate symbols for quantifiers. (c) Write the negation of the statement in part (b) in symbolic form using appropriate symbols for quantifiers. (d) Write the negation from part (c) in English without usings the symbols for quantifiers.

(b) ∀x∈ℝ ∃ y∈ℝ: xy=1

(c)∀x∈ℝ ∄ y∈ℝ: xy=1

Step-by-step explanation:

(a)For each x∈ℝ , there exists a y∈ℝ such that xy=1.

Given x=2∈ℝ

xy=1

2y=1

But ∉ℝ.

In fact, ∈ℚ, the set of Rational Numbers.

Therefore, the statement is false.

(b) ∀x∈ℝ ∃ y∈ℝ: xy=1

(c)∀x∈ℝ ∄ y∈ℝ: xy=1

(d)For each x in the set of Real numbers , there does not exists a y in the set of real numbers such that such that xy=1.

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

answer: i guess 105 degrees?

step-by-step explanation: