What are the coordinates of the vertex of the function f(x)=x^2+10x-3

(-5,-28)

Step-by-step explanation:

f(x)=x^2+10x-3

Axis of symmetry is -b/2a.

-10/2 = -5. This is the x value of the vertex.

Plug in to solve for y.

-5^2+10(-5)-3 = -28.

what is the question?

step-by-step explanation:

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.